We haven’t had a string question for a while (5 days to be precise), so
let’s go for one.
文字列 s と正の整数 n が与えられたら、 s
のすべての n > n 回、それを s に戻します。
For example, if n = 3 and s = "Hello,, every third character is
World!"Hl r!. You
then repeat each character n times to produce
HHHlll rrr!!!. You then replace the original letters
with the repeated versions to produce the final product of
HHHellllo, Worrrld!!!
可能な限り最短のコードでこのタスクを実行する必要があります。
ルール
- This is a code-golf so the shortest code in bytes wins
-
nis guaranteed to be smaller than the length of
sand greater than 0 - The first character of
sis where the
nth characters are taken from, and is always repeated
ntimes -
swill only consist of printable ASCII (code
points0x20 (space)to0x7E (~))
テストケース
s, n => output
"Hello, World!", 3 => "HHHellllo, Worrrld!!!"
"Code golf", 1 => "Code golf"
"abcdefghijklm", 10 => "aaaaaaaaaabcdefghijkkkkkkkkkklm"
"tesTing", 6 => "ttttttesTingggggg"
"very very very long string for you to really make sure that your program works", 4 => "vvvvery veryyyy verrrry loooong sssstrinnnng foooor yoooou toooo reaaaally makeeee surrrre thhhhat yyyyour proggggram workkkks"
ベストアンサー
Jelly, 6 5 bytes
漏洩Nunのおかげで-1バイト（Pythonの文字列の乗算を使用します）。
×Jm¥¦
2つのコマンドライン引数、文字列と数値を受け取り、結果を出力する完全なプログラム。
どうやって？
×Jm¥¦ - Main link: list of characters, s; number, n e.g. ['g','o','l','f','e','r'], 2
¦ - sparse application:
¥ - ...to indices: last two links as a dyad:
J - range of length of s [1,2,3,4,5,6]
m - modulo slicing by n (every nth entry) [1,3,5]
× - ...action: multiply ["gg",'o',"ll",'f',"ee",'r']
- implicit print >>> ggollfeer